(2x^-3y^-1/-8x^2y^-4)^-2

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Solution for (2x^-3y^-1/-8x^2y^-4)^-2 equation: 


D( x )

x = 0

x^2*((2*x^-3*y^-1)/(-8))*y^-4 = 0

x = 0

x = 0

x^2*((2*x^-3*y^-1)/(-8))*y^-4 = 0

x^2*((2*x^-3*y^-1)/(-8))*y^-4 = 0

-1/4*x^-1*y^-5 = 0 // : -1/4*y^-5

x^-1 = 0

x należy do O

x in (-oo:0) U (0:+oo)

(x^2*((2*x^-3*y^-1)/(-8))*y^-4)^-2 = 0

16*x^2*y^10 = 0 // : 16*y^10

x^2 = 0

x = 0

x in { 0} 

x belongs to the empty set

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